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(3/n)+(1/6)=(11/(3n))
We move all terms to the left:
(3/n)+(1/6)-((11/(3n)))=0
Domain of the equation: n)!=0
n!=0/1
n!=0
n∈R
Domain of the equation: 3n))!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
(+3/n)-((+11/3n))+(+1/6)=0
We get rid of parentheses
3/n-((+11/3n))+1/6=0
We calculate fractions
(-((+11*n*6)/18n^2+9n^2/18n^2+54n/18n^2=0
We can not solve this equation
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