(3/8f)+1/2=6((1/16)f)-3

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Solution for (3/8f)+1/2=6((1/16)f)-3 equation: 


f in (-oo:+oo)

(3/8)*f+1/2 = 6*(1/16)*f-3 // - 6*(1/16)*f-3

(3/8)*f-(6*(1/16)*f)+1/2+3 = 0

(3/8)*f+(-3/8)*f+1/2+3 = 0

7/2 = 0

f belongs to the empty set

f belongs to the empty set

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