(3/7y)-(1/4)=(5/y)

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Solution for (3/7y)-(1/4)=(5/y) equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(3/7)*y-(1/4) = 5/y // - 5/y

(3/7)*y-(5/y)-(1/4) = 0

(3/7)*y-5*y^-1-1/4 = 0

3/7*y^1-5*y^-1-1/4*y^0 = 0

(3/7*y^2-1/4*y^1-5*y^0)/(y^1) = 0 // * y^2

y^1*(3/7*y^2-1/4*y^1-5*y^0) = 0

y^1

(3/7)*y^2+(-1/4)*y-5 = 0

(3/7)*y^2+(-1/4)*y-5 = 0

DELTA = (-1/4)^2-(-5*4*(3/7))

DELTA = 967/112

DELTA > 0

y = ((967/112)^(1/2)-(-1/4))/(2*(3/7)) or y = (-(-1/4)-(967/112)^(1/2))/(2*(3/7))

y = 7/6*((967/112)^(1/2)+1/4) or y = 7/6*(1/4-(967/112)^(1/2))

y in { 7/6*(1/4-(967/112)^(1/2)), 7/6*((967/112)^(1/2)+1/4)}

y in { 7/6*(1/4-(967/112)^(1/2)), 7/6*((967/112)^(1/2)+1/4) }

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