(3/7)(3x-1)=1/2

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Solution for (3/7)(3x-1)=1/2 equation: 



(3/7)(3x-1)=1/2

We move all terms to the left:

(3/7)(3x-1)-(1/2)=0



Domain of the equation: 7)(3x-1)!=0

x∈R



We add all the numbers together, and all the variables

(+3/7)(3x-1)-(+1/2)=0

We get rid of parentheses

(+3/7)(3x-1)-1/2=0

We multiply parentheses ..

(+9x^2+3/7*-1)-1/2=0

We calculate fractions


((+9x^2+3*2)/()+()/()=0



We calculate terms in parentheses: +((+9x^2+3*2)/()+()/(), so:

(+9x^2+3*2)/()+()/(

We add all the numbers together, and all the variables

(+9x^2+3*2)/()+1

We multiply all the terms by the denominator


(+9x^2+3*2)+1*()

We add all the numbers together, and all the variables

(+9x^2+3*2)

We get rid of parentheses

9x^2+3*2

We add all the numbers together, and all the variables

9x^2+6

Back to the equation:

+(9x^2+6)



We get rid of parentheses

9x^2+6=0

a = 9; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·9·6
Δ = -216
Delta is less than zero, so there is no solution for the equation

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