(3/5)y+2=1y

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Solution for (3/5)y+2=1y equation: 



(3/5)y+2=1y

We move all terms to the left:

(3/5)y+2-(1y)=0



Domain of the equation: 5)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+3/5)y-1y+2=0

We add all the numbers together, and all the variables

-1y+(+3/5)y+2=0

We multiply parentheses

3y^2-1y+2=0

a = 3; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·3·2
Δ = -23
Delta is less than zero, so there is no solution for the equation

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