(3/5)(x-7)=(7/10)(x+2)

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Solution for (3/5)(x-7)=(7/10)(x+2) equation: 



(3/5)(x-7)=(7/10)(x+2)

We move all terms to the left:

(3/5)(x-7)-((7/10)(x+2))=0



Domain of the equation: 5)(x-7)!=0

x∈R





Domain of the equation: 10)(x+2))!=0

x∈R



We add all the numbers together, and all the variables

(+3/5)(x-7)-((+7/10)(x+2))=0

We multiply parentheses ..

(+3x^2+3/5*-7)-((+7/10)(x+2))=0

We calculate fractions


((+3x^2+3*10)(x+2)))/(-7)*10)(x+2))+5*)+()/(-7)*10)(x+2))+5*)=0

We calculate fractions


(((+3x^2+3*10)(x+2)))*(-7)*10)(x+2))+5*))/((*(-7)*10)x)+(-7)*10)(x+2))+5*)+()*()/((*(-7)*10)x)=0

We can not solve this equation

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