(3/5)(2x-1)=4

Solution for (3/5)(2x-1)=4 equation:

(3/5)(2x-1)=4

We move all terms to the left:

(3/5)(2x-1)-(4)=0


Domain of the equation: 5)(2x-1)!=0

x∈R


We add all the numbers together, and all the variables

(+3/5)(2x-1)-4=0

We multiply parentheses ..

(+6x^2+3/5*-1)-4=0

We multiply all the terms by the denominator


(+6x^2+3-4*5*-1)=0

We get rid of parentheses

6x^2+3-1-4*5*=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$