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(3/5(x+2)=x-4
We move all terms to the left:
(3/5(x+2)-(x-4)=0
Domain of the equation: 5(x+2)-(x-4)!=0We multiply all the terms by the denominator
x∈R
(3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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