(3/4m)-(1/8m)=5

Solution for (3/4m)-(1/8m)=5 equation:

(3/4m)-(1/8m)=5

We move all terms to the left:

(3/4m)-(1/8m)-(5)=0


Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R



Domain of the equation: 8m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+3/4m)-(+1/8m)-5=0

We get rid of parentheses

3/4m-1/8m-5=0

We calculate fractions


24m/32m^2+(-4m)/32m^2-5=0

We multiply all the terms by the denominator


24m+(-4m)-5*32m^2=0

Wy multiply elements

-160m^2+24m+(-4m)=0

We get rid of parentheses

-160m^2+24m-4m=0

We add all the numbers together, and all the variables

-160m^2+20m=0

a = -160; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-160)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-160}=\frac{-40}{-320}
=1/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-160}=\frac{0}{-320}
=0
$