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(3/4)z-(1/4)z+3=(2/4)z+5
We move all terms to the left:
(3/4)z-(1/4)z+3-((2/4)z+5)=0
Domain of the equation: 4)z!=0
z!=0/1
z!=0
z∈R
Domain of the equation: 4)z+5)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
(+3/4)z-(+1/4)z-((+2/4)z+5)+3=0
We multiply parentheses
3z^2-z^2-((+2/4)z+5)+3=0
We multiply all the terms by the denominator
3z^2*4)z+5)-z^2*4)z+5)-((+2+3*4)z+5)=0
We add all the numbers together, and all the variables
3z^2*4)z+5)-z^2*4)z+5)-(14z+5)=0
Wy multiply elements
48z^4=0
We do not support ezpression: z^4
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