(3/4)x=27/28

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Solution for (3/4)x=27/28 equation:



(3/4)x=27/28
We move all terms to the left:
(3/4)x-(27/28)=0
Domain of the equation: 4)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+3/4)x-(+27/28)=0
We multiply parentheses
3x^2-(+27/28)=0
We get rid of parentheses
3x^2-27/28=0
We multiply all the terms by the denominator
3x^2*28-27=0
Wy multiply elements
84x^2-27=0
a = 84; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·84·(-27)
Δ = 9072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9072}=\sqrt{1296*7}=\sqrt{1296}*\sqrt{7}=36\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{7}}{2*84}=\frac{0-36\sqrt{7}}{168} =-\frac{36\sqrt{7}}{168} =-\frac{3\sqrt{7}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{7}}{2*84}=\frac{0+36\sqrt{7}}{168} =\frac{36\sqrt{7}}{168} =\frac{3\sqrt{7}}{14} $

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