(3/4)x-1=(7/8)x+4

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Solution for (3/4)x-1=(7/8)x+4 equation:



(3/4)x-1=(7/8)x+4
We move all terms to the left:
(3/4)x-1-((7/8)x+4)=0
Domain of the equation: 4)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 8)x+4)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+3/4)x-((+7/8)x+4)-1=0
We multiply parentheses
3x^2-((+7/8)x+4)-1=0
We multiply all the terms by the denominator
3x^2*8)x+4)-((-1*8)x+4)+7=0
We add all the numbers together, and all the variables
3x^2*8)x+4)-((-8)x+4)+7=0
Wy multiply elements
24x^3-8)x+4)+7=0
We do not support expression: x^3

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