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(3/4)x+2=(5/4)x-6=16
We move all terms to the left:
(3/4)x+2-((5/4)x-6)=0
Domain of the equation: 4)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)x-6)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/4)x-((+5/4)x-6)+2=0
We multiply parentheses
3x^2-((+5/4)x-6)+2=0
We multiply all the terms by the denominator
3x^2*4)x-6)-((+2*4)x-6)+5=0
We add all the numbers together, and all the variables
3x^2*4)x-6)-(8x-6)+5=0
Wy multiply elements
12x^3=0
We do not support expression: x^3
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