(3/4)x+1/2=(7/3)x+4

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Solution for (3/4)x+1/2=(7/3)x+4 equation: 



(3/4)x+1/2=(7/3)x+4

We move all terms to the left:

(3/4)x+1/2-((7/3)x+4)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)x+4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)x-((+7/3)x+4)+1/2=0

We multiply parentheses

3x^2-((+7/3)x+4)+1/2=0

We calculate fractions


3x^2+()/3x+4)*2)+3x/3x+4)*2)=0

We calculate fractions


3x^2+(()*3x)/9x^2+4*2)+3x*3x)/9x^2=0

We multiply all the terms by the denominator


3x^2*9x^2+(()*3x)+4*2)+3x*3x)=0



We calculate terms in parentheses: +(()*3x), so:

()*3x



Wy multiply elements

27x^4+24x^2+(()*3x)=0



We calculate terms in parentheses: +(()*3x), so:

()*3x



We do not support expression: x^4

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