(3/4)b-6=-12

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Solution for (3/4)b-6=-12 equation: 



(3/4)b-6=-12

We move all terms to the left:

(3/4)b-6-(-12)=0



Domain of the equation: 4)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+3/4)b-6-(-12)=0

We add all the numbers together, and all the variables

(+3/4)b+6=0

We multiply parentheses

3b^2+6=0

a = 3; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·3·6
Δ = -72
Delta is less than zero, so there is no solution for the equation

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