(3/4)(x-3)-(1/2)=(2/3)

Solution for (3/4)(x-3)-(1/2)=(2/3) equation:

(3/4)(x-3)-(1/2)=(2/3)

We move all terms to the left:

(3/4)(x-3)-(1/2)-((2/3))=0


Domain of the equation: 4)(x-3)!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)(x-3)-(+1/2)-((+2/3))=0

We get rid of parentheses

(+3/4)(x-3)-1/2-((+2/3))=0

We multiply parentheses ..

(+3x^2+3/4*-3)-1/2-((+2/3))=0

We calculate fractions


3x^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

3x^2/()+2=0

We multiply all the terms by the denominator


3x^2+2*()=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$