(3/3b+4)=(2/b-4)

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Solution for (3/3b+4)=(2/b-4) equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

(3/3)*b+4 = 2/b-4 // - 2/b-4

(3/3)*b-(2/b)+4+4 = 0

(3/3)*b-2*b^-1+4+4 = 0

1*b^1-2*b^-1+8*b^0 = 0

(1*b^2+8*b^1-2*b^0)/(b^1) = 0 // * b^2

b^1*(1*b^2+8*b^1-2*b^0) = 0

b^1

b^2+8*b-2 = 0

b^2+8*b-2 = 0

DELTA = 8^2-(-2*1*4)

DELTA = 72

DELTA > 0

b = (72^(1/2)-8)/(1*2) or b = (-72^(1/2)-8)/(1*2)

b = (6*2^(1/2)-8)/2 or b = (-6*2^(1/2)-8)/2

b in { (-6*2^(1/2)-8)/2, (6*2^(1/2)-8)/2} 

b in { (-6*2^(1/2)-8)/2, (6*2^(1/2)-8)/2 }

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