(3/2x)-2+(1/2)=(2/x-1)

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Solution for (3/2x)-2+(1/2)=(2/x-1) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/2)*x+1/2-2 = 2/x-1 // - 2/x-1

(3/2)*x-(2/x)+1/2-2+1 = 0

(3/2)*x-2*x^-1+1/2-2+1 = 0

3/2*x^1-2*x^-1-1/2*x^0 = 0

(3/2*x^2-1/2*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2-1/2*x^1-2*x^0) = 0

x^1

(3/2)*x^2+(-1/2)*x-2 = 0

(3/2)*x^2+(-1/2)*x-2 = 0

DELTA = (-1/2)^2-(-2*4*(3/2))

DELTA = 49/4

DELTA > 0

x = ((49/4)^(1/2)-(-1/2))/(2*(3/2)) or x = (-(-1/2)-(49/4)^(1/2))/(2*(3/2))

x = 4/3 or x = -1

x in { -1, 4/3} 

x in { -1, 4/3 }

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