(3/2x)-(1/x-5)=1

Solution for (3/2x)-(1/x-5)=1 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/2)*x-(1/x)+5 = 1 // - 1

(3/2)*x-(1/x)-1+5 = 0

(3/2)*x-x^-1-1+5 = 0

3/2*x^1-1*x^-1+4*x^0 = 0

(3/2*x^2+4*x^1-1*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2+4*x^1-1*x^0) = 0

x^1

(3/2)*x^2+4*x-1 = 0

(3/2)*x^2+4*x-1 = 0

DELTA = 4^2-(-1*4*(3/2))

DELTA = 22

DELTA > 0

x = (22^(1/2)-4)/(2*(3/2)) or x = (-22^(1/2)-4)/(2*(3/2))

x = (22^(1/2)-4)/3 or x = (-(22^(1/2)+4))/3

x in { (-(22^(1/2)+4))/3, (22^(1/2)-4)/3} 

x in { (-(22^(1/2)+4))/3, (22^(1/2)-4)/3 }