(3/2x)+(1/3x)=1

Solution for (3/2x)+(1/3x)=1 equation:

(3/2x)+(1/3x)=1

We move all terms to the left:

(3/2x)+(1/3x)-(1)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/2x)+(+1/3x)-1=0

We get rid of parentheses

3/2x+1/3x-1=0

We calculate fractions


9x/6x^2+2x/6x^2-1=0

We multiply all the terms by the denominator


9x+2x-1*6x^2=0

We add all the numbers together, and all the variables

11x-1*6x^2=0

Wy multiply elements

-6x^2+11x=0

a = -6; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-6)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-6}=\frac{-22}{-12}
=1+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-6}=\frac{0}{-12}
=0
$