(3/2)z+5=(z/4)+20

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Solution for (3/2)z+5=(z/4)+20 equation: 



(3/2)z+5=(z/4)+20

We move all terms to the left:

(3/2)z+5-((z/4)+20)=0



Domain of the equation: 2)z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+3/2)z-((+z/4)+20)+5=0

We multiply parentheses

3z^2-((+z/4)+20)+5=0

We multiply all the terms by the denominator


3z^2*4)+20)-((+z+5*4)+20)=0

We add all the numbers together, and all the variables

3z^2*4)+20)-((z+20)+20)=0

We add all the numbers together, and all the variables

3z^2*4)+20)-((z=0

Wy multiply elements

12z^3=0

We do not support ezpression: z^3

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