(3/2)x+5=5-2(x+7)

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Solution for (3/2)x+5=5-2(x+7) equation: 



(3/2)x+5=5-2(x+7)

We move all terms to the left:

(3/2)x+5-(5-2(x+7))=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/2)x-(5-2(x+7))+5=0

We multiply parentheses

3x^2-(5-2(x+7))+5=0



We calculate terms in parentheses: -(5-2(x+7)), so:

5-2(x+7)

determiningTheFunctionDomain
-2(x+7)+5

We multiply parentheses

-2x-14+5

We add all the numbers together, and all the variables

-2x-9

Back to the equation:

-(-2x-9)



We get rid of parentheses

3x^2+2x+9+5=0

We add all the numbers together, and all the variables

3x^2+2x+14=0

a = 3; b = 2; c = +14;
Δ = b2-4ac
Δ = 22-4·3·14
Δ = -164
Delta is less than zero, so there is no solution for the equation

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