(3/2)w-(3/5)=(-7/5)w-7

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Solution for (3/2)w-(3/5)=(-7/5)w-7 equation: 



(3/2)w-(3/5)=(-7/5)w-7

We move all terms to the left:

(3/2)w-(3/5)-((-7/5)w-7)=0



Domain of the equation: 2)w!=0

w!=0/1

w!=0

w∈R





Domain of the equation: 5)w-7)!=0

w!=0/1

w!=0

w∈R



We add all the numbers together, and all the variables

(+3/2)w-((-7/5)w-7)-(+3/5)=0

We multiply parentheses

3w^2-((-7/5)w-7)-(+3/5)=0

We get rid of parentheses

3w^2-((-7/5)w-7)-3/5=0

We calculate fractions


3w^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{6}=0$

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