(3/2)t-16=(4/3)t-6

Solution for (3/2)t-16=(4/3)t-6 equation:

(3/2)t-16=(4/3)t-6

We move all terms to the left:

(3/2)t-16-((4/3)t-6)=0


Domain of the equation: 2)t!=0

t!=0/1

t!=0

t∈R



Domain of the equation: 3)t-6)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+3/2)t-((+4/3)t-6)-16=0

We multiply parentheses

3t^2-((+4/3)t-6)-16=0

We multiply all the terms by the denominator


3t^2*3)t-6)-((-16*3)t-6)+4=0

We add all the numbers together, and all the variables

3t^2*3)t-6)-((-48)t-6)+4=0

Wy multiply elements

9t^3-48)t-6)+4=0

We do not support etpression: t^3