(3/2)*x+x-4*x-11+2=0

Solution for (3/2)*x+x-4*x-11+2=0 equation:

(3/2)*x+x-4x-11+2=0


Domain of the equation: 2)*x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/2)*x+x-4x-11+2=0

We add all the numbers together, and all the variables

-3x+(+3/2)*x-9=0

We multiply parentheses

3x^2-3x-9=0

a = 3; b = -3; c = -9;
Δ = b2-4ac
Δ = -32-4·3·(-9)
Δ = 117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{117}=\sqrt{9*13}=\sqrt{9}*\sqrt{13}=3\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{13}}{2*3}=\frac{3-3\sqrt{13}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{13}}{2*3}=\frac{3+3\sqrt{13}}{6}
$