(3/10)a+6=9

Solution for (3/10)a+6=9 equation:

(3/10)a+6=9

We move all terms to the left:

(3/10)a+6-(9)=0


Domain of the equation: 10)a!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

(+3/10)a+6-9=0

We add all the numbers together, and all the variables

(+3/10)a-3=0

We multiply parentheses

3a^2-3=0

a = 3; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·3·(-3)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*3}=\frac{-6}{6}
=-1
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*3}=\frac{6}{6}
=1
$