(3/(x-1))+(2/(2x+3))=5

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Solution for (3/(x-1))+(2/(2x+3))=5 equation: 



(3/(x-1))+(2/(2x+3))=5

We move all terms to the left:

(3/(x-1))+(2/(2x+3))-(5)=0



Domain of the equation: (x-1))!=0

x∈R





Domain of the equation: (2x+3))!=0

x∈R



We calculate fractions


(6x+9)/((x-1))*2x+(2x-2)/((x-1))*2x-5=0

We multiply all the terms by the denominator


(6x+9)+(2x-2)-5*((x-1))*2x=0

We get rid of parentheses

6x+2x-5*((x-1))*2x+9-2=0

We add all the numbers together, and all the variables

8x-5*((x-1))*2x+7=0

We move all terms containing x to the left, all other terms to the right

8x-5*((x-1))*2x=-7

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