(3/(x+1))+((x-2)/2)=(x-2)/(x+1)

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Solution for (3/(x+1))+((x-2)/2)=(x-2)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

3/(x+1)+(x-2)/2 = (x-2)/(x+1) // - (x-2)/(x+1)

3/(x+1)+(x-2)/2-((x-2)/(x+1)) = 0

3/(x+1)+(x-2)/2+(-1*(x-2))/(x+1) = 0

(2*3)/(2*(x+1))+((x-2)*(x+1))/(2*(x+1))+(-1*2*(x-2))/(2*(x+1)) = 0

(x-2)*(x+1)-1*2*(x-2)+2*3 = 0

x^2-x-2*x+4+4 = 0

x^2-3*x+8 = 0

x^2-3*x+8 = 0

x^2-3*x+8 = 0

DELTA = (-3)^2-(1*4*8)

DELTA = -23

DELTA < 0

1 = 0

1/(2*(x+1)) = 0

1/(2*(x+1)) = 0 // * 2*(x+1)

1 = 0

x belongs to the empty set

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