(3/(4x))+(1/(2x^2))=(1/(8x))

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Solution for (3/(4x))+(1/(2x^2))=(1/(8x)) equation: 


D( x )

8*x = 0

4*x = 0

2*x^2 = 0

8*x = 0

8*x = 0

8*x = 0 // : 8

x = 0

4*x = 0

4*x = 0

4*x = 0 // : 4

x = 0

2*x^2 = 0

2*x^2 = 0

2*x^2 = 0 // : 2

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/(4*x)+1/(2*x^2) = 1/(8*x) // - 1/(8*x)

3/(4*x)-(1/(8*x))+1/(2*x^2) = 0

3/(4*x)+(-1/8)*x^-1+1/(2*x^2) = 0

5/8*x^-1+1/2*x^-2 = 0

t_1 = x^-1

1/2*t_1^2+5/8*t_1^1 = 0

1/2*t_1^2+5/8*t_1 = 0

DELTA = (5/8)^2-(0*1/2*4)

DELTA = 25/64

DELTA > 0

t_1 = ((25/64)^(1/2)-5/8)/(1/2*2) or t_1 = (-(25/64)^(1/2)-5/8)/(1/2*2)

t_1 = 0 or t_1 = -5/4

t_1 = -5/4

x^-1+5/4 = 0

1*x^-1 = -5/4 // : 1

x^-1 = -5/4

-1 < 0

1/(x^1) = -5/4 // * x^1

1 = -5/4*x^1 // : -5/4

-4/5 = x^1

x = -4/5

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -4/5

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