(3/(2n-1))-(3/(1-2n))

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Solution for (3/(2n-1))-(3/(1-2n)) equation: 


D( n )

1-(2*n) = 0

2*n-1 = 0

1-(2*n) = 0

1-(2*n) = 0

1-2*n = 0

1-2*n = 0 // - 1

-2*n = -1 // : -2

n = -1/(-2)

n = 1/2

2*n-1 = 0

2*n-1 = 0

2*n-1 = 0 // + 1

2*n = 1 // : 2

n = 1/2

n in (-oo:1/2) U (1/2:+oo)

3/(2*n-1)-(3/(1-(2*n))) = 0

3/(2*n-1)-3*(1-2*n)^-1 = 0

3/(2*n-1)-3/(1-2*n) = 0

(3*(1-2*n))/((2*n-1)*(1-2*n))+(-3*(2*n-1))/((2*n-1)*(1-2*n)) = 0

3*(1-2*n)-3*(2*n-1) = 0

6-12*n = 0

(6-12*n)/((2*n-1)*(1-2*n)) = 0

(6-12*n)/((2*n-1)*(1-2*n)) = 0 // * (2*n-1)*(1-2*n)

6-12*n = 0

6-12*n = 0 // - 6

-12*n = -6 // : -12

n = -6/(-12)

n = 1/2

n in { 1/2} 

n belongs to the empty set

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