(3.6/2)v+10=9v+9

Solution for (3.6/2)v+10=9v+9 equation:

(3.6/2)v+10=9v+9

We move all terms to the left:

(3.6/2)v+10-(9v+9)=0


Domain of the equation: 2)v!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

(+3.6/2)v-(9v+9)+10=0

We multiply parentheses

3v^2-(9v+9)+10=0

We get rid of parentheses

3v^2-9v-9+10=0

We add all the numbers together, and all the variables

3v^2-9v+1=0

a = 3; b = -9; c = +1;
Δ = b2-4ac
Δ = -92-4·3·1
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{69}}{2*3}=\frac{9-\sqrt{69}}{6}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{69}}{2*3}=\frac{9+\sqrt{69}}{6}
$