(3-y)(3-y)=0

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Solution for (3-y)(3-y)=0 equation: 



(3-y)(3-y)=0

We add all the numbers together, and all the variables

(-1y+3)(-1y+3)=0

We multiply parentheses ..

(+y^2-3y-3y+9)=0

We get rid of parentheses

y^2-3y-3y+9=0

We add all the numbers together, and all the variables

y^2-6y+9=0

a = 1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{6}{2}=3$

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