(3-y)(3+y)=

Solution for (3-y)(3+y)= equation:

Simplifying
(3 + -1y)(3 + y) = 0

Multiply (3 + -1y) * (3 + y)
(3(3 + y) + -1y * (3 + y)) = 0
((3 * 3 + y * 3) + -1y * (3 + y)) = 0
((9 + 3y) + -1y * (3 + y)) = 0
(9 + 3y + (3 * -1y + y * -1y)) = 0
(9 + 3y + (-3y + -1y2)) = 0

Combine like terms: 3y + -3y = 0
(9 + 0 + -1y2) = 0
(9 + -1y2) = 0

Solving
9 + -1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1y2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1y2 = 0 + -9
-1y2 = 0 + -9

Combine like terms: 0 + -9 = -9
-1y2 = -9

Divide each side by '-1'.
y2 = 9

Simplifying
y2 = 9

Take the square root of each side:
y = {-3, 3}