(3-y)(2y+3)=0

Solution for (3-y)(2y+3)=0 equation:

(3-y)(2y+3)=0

We add all the numbers together, and all the variables

(-1y+3)(2y+3)=0

We multiply parentheses ..

(-2y^2-3y+6y+9)=0

We get rid of parentheses

-2y^2-3y+6y+9=0

We add all the numbers together, and all the variables

-2y^2+3y+9=0

a = -2; b = 3; c = +9;
Δ = b2-4ac
Δ = 32-4·(-2)·9
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*-2}=\frac{-12}{-4}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*-2}=\frac{6}{-4}
=-1+1/2
$