(3-x)/5+(3x-1)/4+4+(12-5x)/3=x-(12-5x)/3+1

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Solution for (3-x)/5+(3x-1)/4+4+(12-5x)/3=x-(12-5x)/3+1 equation: 



(3-x)/5+(3x-1)/4+4+(12-5x)/3=x-(12-5x)/3+1

We move all terms to the left:

(3-x)/5+(3x-1)/4+4+(12-5x)/3-(x-(12-5x)/3+1)=0

We add all the numbers together, and all the variables

(-1x+3)/5+(3x-1)/4+(-5x+12)/3-(x-(-5x+12)/3+1)+4=0

We calculate fractions


((-1x+3)*4*3*3)/()+((3x-1)*5*3*3)/()+((-5x+12)*5*4)/()+(-(x-(-5x+12)*5*4)/()+4=0



We calculate terms in parentheses: +((-1x+3)*4*3*3)/(), so:

(-1x+3)*4*3*3)/(

We multiply all the terms by the denominator


(-1x+3)*4*3*3)

We get rid of parentheses

-1x+3)*4*3*3

We add all the numbers together, and all the variables

-x

Back to the equation:

+(-x)





We calculate terms in parentheses: +((3x-1)*5*3*3)/(), so:

(3x-1)*5*3*3)/(

We multiply all the terms by the denominator


(3x-1)*5*3*3)

We get rid of parentheses

3x-1)*5*3*3

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +((-5x+12)*5*4)/(), so:

(-5x+12)*5*4)/(

We multiply all the terms by the denominator


(-5x+12)*5*4)

We get rid of parentheses

-5x+12)*5*4

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)



We add all the numbers together, and all the variables

(-1x)+3x+(-5x)+(-(x-(-5x+12)*5*4)/()+4=0

We add all the numbers together, and all the variables

3x+(-1x)+(-5x)+(-(x-(-5x+12)*5*4)/()+4=0

We get rid of parentheses

3x-1x-5x+(-(x-(-5x+12)*5*4)/()+4=0

We multiply all the terms by the denominator


3x*()-1x*()-5x*()+(-(x-(-5x+12)*5*4)+4+4+4=0

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