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(3-x)(-x)-18=x(x-6)
We move all terms to the left:
(3-x)(-x)-18-(x(x-6))=0
We add all the numbers together, and all the variables
(-1x+3)(-1x)-(x(x-6))-18=0
We multiply parentheses ..
(+x^2-3x)-(x(x-6))-18=0
We calculate terms in parentheses: -(x(x-6)), so:We get rid of parentheses
x(x-6)
We multiply parentheses
x^2-6x
Back to the equation:
-(x^2-6x)
x^2-x^2-3x+6x-18=0
We add all the numbers together, and all the variables
3x-18=0
We move all terms containing x to the left, all other terms to the right
3x=18
x=18/3
x=6
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