(3-v)(2v-1)=0

Solution for (3-v)(2v-1)=0 equation:

(3-v)(2v-1)=0

We add all the numbers together, and all the variables

(-1v+3)(2v-1)=0

We multiply parentheses ..

(-2v^2+v+6v-3)=0

We get rid of parentheses

-2v^2+v+6v-3=0

We add all the numbers together, and all the variables

-2v^2+7v-3=0

a = -2; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·(-2)·(-3)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*-2}=\frac{-12}{-4}
=+3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*-2}=\frac{-2}{-4}
=1/2
$