(3-7i)(3-7i)=0

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Solution for (3-7i)(3-7i)=0 equation: 



(3-7i)(3-7i)=0

We add all the numbers together, and all the variables

(-7i+3)(-7i+3)=0

We multiply parentheses ..

(+49i^2-21i-21i+9)=0

We get rid of parentheses

49i^2-21i-21i+9=0

We add all the numbers together, and all the variables

49i^2-42i+9=0

a = 49; b = -42; c = +9;
Δ = b2-4ac
Δ = -422-4·49·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{42}{98}=3/7$

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