(3-6x)(4x+3)=0

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Solution for (3-6x)(4x+3)=0 equation:



(3-6x)(4x+3)=0
We add all the numbers together, and all the variables
(-6x+3)(4x+3)=0
We multiply parentheses ..
(-24x^2-18x+12x+9)=0
We get rid of parentheses
-24x^2-18x+12x+9=0
We add all the numbers together, and all the variables
-24x^2-6x+9=0
a = -24; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·(-24)·9
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*-24}=\frac{-24}{-48} =1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*-24}=\frac{36}{-48} =-3/4 $

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