(3-4j)(3j-2)/-j

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Solution for (3-4j)(3j-2)/-j equation:


D( j )

-j = 0

-j = 0

j = 0

j in (-oo:0) U (0:+oo)

((3-(4*j))*(3*j-2))/(-j) = 0

((3-4*j)*(3*j-2))/(-j) = 0

( 3*j-2 )

3*j-2 = 0 // + 2

3*j = 2 // : 3

j = 2/3

( 3-4*j )

3-4*j = 0 // - 3

-4*j = -3 // : -4

j = -3/(-4)

j = 3/4

j in { 2/3, 3/4 }

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