(3-2j)*(4-2j)=(8-14j)

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Solution for (3-2j)*(4-2j)=(8-14j) equation: 



(3-2j)(4-2j)=(8-14j)

We move all terms to the left:

(3-2j)(4-2j)-((8-14j))=0

We add all the numbers together, and all the variables

(-2j+3)(-2j+4)-((-14j+8))=0

We multiply parentheses ..

(+4j^2-8j-6j+12)-((-14j+8))=0



We calculate terms in parentheses: -((-14j+8)), so:

(-14j+8)

We get rid of parentheses

-14j+8

Back to the equation:

-(-14j+8)



We get rid of parentheses

4j^2-8j-6j+14j+12-8=0

We add all the numbers together, and all the variables

4j^2+4=0

a = 4; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·4·4
Δ = -64
Delta is less than zero, so there is no solution for the equation

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