(3+y)/4=(-y)/8

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Solution for (3+y)/4=(-y)/8 equation: 



(3+y)/4=(-y)/8

We move all terms to the left:

(3+y)/4-((-y)/8)=0

We add all the numbers together, and all the variables

(y+3)/4-((-1y)/8)=0

We calculate fractions


y/()+(-((-1y)*4)/()=0



We calculate terms in parentheses: +(-((-1y)*4)/(), so:

-((-1y)*4)/(

We multiply all the terms by the denominator


-((-1y)*4)



We calculate terms in parentheses: -((-1y)*4), so:

(-1y)*4

We multiply parentheses

-4y

Back to the equation:

-(-4y)



We get rid of parentheses

4y

Back to the equation:

+(4y)



We add all the numbers together, and all the variables

4y+y/()=0

We multiply all the terms by the denominator


4y*()+y=0

We add all the numbers together, and all the variables

y+4y*()=0

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