(3+y)(5y+8)=0

Solution for (3+y)(5y+8)=0 equation:

(3+y)(5y+8)=0

We add all the numbers together, and all the variables

(y+3)(5y+8)=0

We multiply parentheses ..

(+5y^2+8y+15y+24)=0

We get rid of parentheses

5y^2+8y+15y+24=0

We add all the numbers together, and all the variables

5y^2+23y+24=0

a = 5; b = 23; c = +24;
Δ = b2-4ac
Δ = 232-4·5·24
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*5}=\frac{-30}{10}
=-3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*5}=\frac{-16}{10}
=-1+3/5
$