(3+x)/(3-x)=1/2

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Solution for (3+x)/(3-x)=1/2 equation: 



(3+x)/(3-x)=1/2

We move all terms to the left:

(3+x)/(3-x)-(1/2)=0



Domain of the equation: (3-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-3

x!=-3/-1

x!=+3

x∈R



We add all the numbers together, and all the variables

(x+3)/(-1x+3)-(+1/2)=0

We get rid of parentheses

(x+3)/(-1x+3)-1/2=0

We calculate fractions


(2x+6)/(-2x+6)+(-1*(-1x+3))/(-2x+6)=0



We calculate terms in parentheses: +(-1*(-1x+3))/(-2x+6), so:

-1*(-1x+3))/(-2x+6

We add all the numbers together, and all the variables

-2x-1*(-1x+3))/(+6

We multiply all the terms by the denominator


-2x*(-1*(-1x+3))+6*(

We add all the numbers together, and all the variables

-2x*(-1*(-1x+3))

Back to the equation:

+(-2x*(-1*(-1x+3)))



We multiply all the terms by the denominator


(2x+6)+((-2x*(-1*(-1x+3))))*(-2x+6)=0



We calculate terms in parentheses: +((-2x*(-1*(-1x+3))))*(-2x+6), so:

(-2x*(-1*(-1x+3))))*(-2x+6

We add all the numbers together, and all the variables

-2x+(-2x*(-1*(-1x+3))))*(+6

Back to the equation:

+(-2x+(-2x*(-1*(-1x+3))))*(+6)



We add all the numbers together, and all the variables

(2x+6)+(-2x+(-2x*(-1*(-1x+3))))*6=0

We get rid of parentheses

2x+(-2x+(-2x*(-1*(-1x+3))))*6+6=0

We move all terms containing x to the left, all other terms to the right

2x+(-2x+(-2x*(-1*(-1x+3))))*6=-6

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