(3+w)(4w+7)=0

Solution for (3+w)(4w+7)=0 equation:

(3+w)(4w+7)=0

We add all the numbers together, and all the variables

(w+3)(4w+7)=0

We multiply parentheses ..

(+4w^2+7w+12w+21)=0

We get rid of parentheses

4w^2+7w+12w+21=0

We add all the numbers together, and all the variables

4w^2+19w+21=0

a = 4; b = 19; c = +21;
Δ = b2-4ac
Δ = 192-4·4·21
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-5}{2*4}=\frac{-24}{8}
=-3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+5}{2*4}=\frac{-14}{8}
=-1+3/4
$