(3+6x)-(2x-27)=6(x+3)+(2x-28)

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Solution for (3+6x)-(2x-27)=6(x+3)+(2x-28) equation: 



(3+6x)-(2x-27)=6(x+3)+(2x-28)

We move all terms to the left:

(3+6x)-(2x-27)-(6(x+3)+(2x-28))=0

We add all the numbers together, and all the variables

(6x+3)-(2x-27)-(6(x+3)+(2x-28))=0

We get rid of parentheses

6x-2x-(6(x+3)+(2x-28))+3+27=0



We calculate terms in parentheses: -(6(x+3)+(2x-28)), so:

6(x+3)+(2x-28)

We multiply parentheses

6x+(2x-28)+18

We get rid of parentheses

6x+2x-28+18

We add all the numbers together, and all the variables

8x-10

Back to the equation:

-(8x-10)



We add all the numbers together, and all the variables

4x-(8x-10)+30=0

We get rid of parentheses

4x-8x+10+30=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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