(3+4i)=(7+11i)

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Solution for (3+4i)=(7+11i) equation: 



(3+4i)=(7+11i)

We move all terms to the left:

(3+4i)-((7+11i))=0

We add all the numbers together, and all the variables

(4i+3)-((11i+7))=0

We get rid of parentheses

4i-((11i+7))+3=0



We calculate terms in parentheses: -((11i+7)), so:

(11i+7)

We get rid of parentheses

11i+7

Back to the equation:

-(11i+7)



We get rid of parentheses

4i-11i-7+3=0

We add all the numbers together, and all the variables

-7i-4=0

We move all terms containing i to the left, all other terms to the right

-7i=4

i=4/-7

i=-4/7

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