(3+4i)3-(2-i)3=

Solution for (3+4i)3-(2-i)3= equation:

Simplifying
(3 + 4i) * 3 + -1(2 + -1i) * 3 = 0

Reorder the terms for easier multiplication:
3(3 + 4i) + -1(2 + -1i) * 3 = 0
(3 * 3 + 4i * 3) + -1(2 + -1i) * 3 = 0
(9 + 12i) + -1(2 + -1i) * 3 = 0

Reorder the terms for easier multiplication:
9 + 12i + -1 * 3(2 + -1i) = 0

Multiply -1 * 3
9 + 12i + -3(2 + -1i) = 0
9 + 12i + (2 * -3 + -1i * -3) = 0
9 + 12i + (-6 + 3i) = 0

Reorder the terms:
9 + -6 + 12i + 3i = 0

Combine like terms: 9 + -6 = 3
3 + 12i + 3i = 0

Combine like terms: 12i + 3i = 15i
3 + 15i = 0

Solving
3 + 15i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 15i = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 15i = 0 + -3
15i = 0 + -3

Combine like terms: 0 + -3 = -3
15i = -3

Divide each side by '15'.
i = -0.2

Simplifying
i = -0.2