(3+2y)2+2y=27

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Solution for (3+2y)2+2y=27 equation: 



(3+2y)2+2y=27

We move all terms to the left:

(3+2y)2+2y-(27)=0

We add all the numbers together, and all the variables

(2y+3)2+2y-27=0

We add all the numbers together, and all the variables

2y+(2y+3)2-27=0

We multiply parentheses

2y+4y+6-27=0

We add all the numbers together, and all the variables

6y-21=0

We move all terms containing y to the left, all other terms to the right

6y=21

y=21/6

y=3+1/2

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