(3+2y)/4=(5y+6)/7

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Solution for (3+2y)/4=(5y+6)/7 equation: 



(3+2y)/4=(5y+6)/7

We move all terms to the left:

(3+2y)/4-((5y+6)/7)=0

We add all the numbers together, and all the variables

(2y+3)/4-((5y+6)/7)=0

We calculate fractions


2y/()+(-((5y+6)*4)/()=0



We calculate terms in parentheses: +(-((5y+6)*4)/(), so:

-((5y+6)*4)/(

We multiply all the terms by the denominator


-((5y+6)*4)



We calculate terms in parentheses: -((5y+6)*4), so:

(5y+6)*4

We multiply parentheses

20y+24

Back to the equation:

-(20y+24)



We get rid of parentheses

-20y-24

Back to the equation:

+(-20y-24)



We get rid of parentheses

2y/()-20y-24=0

We multiply all the terms by the denominator


2y-20y*()-24*()=0

We add all the numbers together, and all the variables

2y-20y*()=0

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